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View Full Version : NL20 SH top two pairs against reg



iceTray
03-12-2011, 01:25 PM
So here's the line.The enemy is a solid reg with 21/15 and agressions of 30/19/23. What is your opinion to b/f here. Can his raise be a bluf in sufficient times to shove would be +EV?

$0.10/$0.20 No Limit Holdem
OnGame
5 Players
Hand Conversion Powered by weaktight.com (http://weaktight.com/)

Stacks:
UTG clebon ($26.21)
CO motyesz ($26.96)
BTN vitalik19 ($19.48)
SB saros86 ($41.45)
BB greensatan89 ($19.66)

Pre-Flop: ($0.30, 5 players) motyesz is CO :ah: :th:
1 fold, motyesz raises to $0.70, vitalik19 calls $0.70, saros86 calls $0.60, greensatan89 calls $0.50

Flop: :4d: :ad: :td: ($2.80, 4 players)
saros86 checks, greensatan89 checks, motyesz bets $2, vitalik19 raises to $8.80, saros86 folds, greensatan89 folds, motyesz folds

Final Pot: $13.60

vitalik19 wins $13.26 (net +$3.76)

saros86 lost $0.70
greensatan89 lost $0.70
motyesz lost $2.70

RX450h
03-12-2011, 03:10 PM
Why did you fold top two pairs on this board? I think thats the worst you could do here. Villain's range is full of pair+draw type of hands, but he could possible had AJ or straight draw+flush draw type of hands as well...

babyonboard
03-12-2011, 06:00 PM
i dont think he would here bluff in a 4way pot. with a strong flopped flush he wouldnt raise.
so value hands he plays this way are:

1, we beat: min. 6 max 18 combinations(6 combos contain a diamond)
-A4 2pair(6 combos but if suited: just 2 combos---i dont consider he would call pre with A4o)
-Ax type hands with a fd.: AQ(8 combos, but with the Qd they are just 2 combos), AJ(8 combos, but with the Jd they are just 2 combo) agaist combos containing a diamond we have 55% eq. if he hasnt diamond this is 84%.(this is 12 combos)

2, we are beaten by: 11 combos
-combos of sets are 3 combos of 4's + 1 combo of tens. (since likely he raised with AA pre)=4 combos
-possible cards he made flopflush with: 23(maybe),56,67,78,89, q9,j9=7 combos. if he had qj i think he would just call, and kq is the same. here we have ~18%eq

3, we tie
-AT (4 combos)

(6x55+12x84+11x18+4x50)/number of combos=(330+1008+198+200)/33=52%
plus maybe we have some percentage of folding eq too but not too much. so push seems to be a bit better here but the two decisions are very close.